var httpPostedFileBase = Request.Files.Get("DocumentFileName"); var myFileName = string.Empty; if (httpPostedFileBase != null) { int position = httpPostedFileBase.FileName.LastIndexOf('\\'); myFileName = httpPostedFileBase.FileName.Substring(position + 1); }
This blog is about my history as a software engineer utilizing technologies C#, Java, React, JavaScript, .NET Core, SQL Server , Oracle, GIT, GitHub, Jira, Azure, AWS and HTML5. “I have not failed. I've just found 10,000 ways that won't work.” Thomas A. Edison. Please click on all my ADVERTISING links to help support this blog. Thank you.
Wednesday, October 29, 2014
Get httpPostedFileBase FileName only code or extract last portion of file director path
Friday, October 24, 2014
Wednesday, October 15, 2014
Reading Keys from Web.config file.
Try using the WebConfigurationManager class instead. For example:
C# string userName = WebConfigurationManager.AppSettings["PFUserName"];
OR
VB.NET Dim userName as String = WebConfigurationManager.AppSettings("PFUserName")
Read file using FileStream - Reference - http://www.csharp-examples.net/filestream-read-file/
Read file using FileStream
First create FileStream to open a file for reading. Then call FileStream.Read in a loop until the whole file is read. Finally close the stream.
[C#]using System.IO; public static byte[] ReadFile(string filePath) { byte[] buffer; FileStream fileStream = new FileStream(filePath, FileMode.Open, FileAccess.Read); try { int length = (int)fileStream.Length; // get file length buffer = new byte[length]; // create buffer int count; // actual number of bytes read int sum = 0; // total number of bytes read // read until Read method returns 0 (end of the stream has been reached) while ((count = fileStream.Read(buffer, sum, length - sum)) > 0) sum += count; // sum is a buffer offset for next reading } finally { fileStream.Close(); } return buffer; }
Wednesday, October 01, 2014
jQuery $.ajax call add functions you will need to call after the html is rendered.
I am adding the following blog post because I spent a good amount of time working on figuring the following out.
Using the jQuery function $.ajax I learned that you need to be sure to add all the functions you want to perform actions on after the $.ajax loads the new content to the page.
CORRECT CODE
<script type="text/javascript">
$("#addItem").click(function () {
$.ajax({
url: this.href,
cache: false,
success: function (html) {
$("#editorRows").append(html);
$("a.deleteRow").on("click", function () {
$(this).parents("div.editorRow:first").remove();
return false;
});
}
});
return false;
});
</script>
This makes 100% sense because if you code it as follows it will never work because the .append(html) is not on the page currently when the jQuery loads.
BAD CODE
<script type="text/javascript">
$("#addItem").click(function () {
$.ajax({
url: this.href,
cache: false,
success: function (html) {
$("#editorRows").append(html);
}
});
return false;
});
//Following will not be called --- because it is not on the page currently
$("a.deleteRow").on("click", function () {
$(this).parents("div.editorRow:first").remove();
return false;
});
</script>
Hope this helps. Have fun coding.
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